Which term of an A.P. 5, 15, 25,………………. will be 130 more than its 31st term?

a=5,d=10 31st term =a+30d =5+30*10=5+300 =305 Given 5,15,25…..will be 139 more than 31st term. So add 130+31st term =130+305=435 Now a+(n-1)d 435=5+(n-1)10 435=5+10n-10 435=-5+10n 435+5=10n 440=10n n=440/10=44th term

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