two AP have the same common difference.the difference between their 100th terms is 100, what is the difference between their 1000th term ?
Let the first AP is represented as TA = a1 + (n1-1)d , where a is the first term and d is the common difference , n1 is the number of terms in AP1.
Let the second AP be represented as TB = a2 + (n2-1)d.
Now , 100th term of TA is TA100 = a1 + 99d
Similarly, 100th term of TB is TB100 = a2+99d
TB100 – TA100 = (a2 – a1) = 100
TA1000 – TB1000 = (a2 + 999d) – (a1 + 999d)
The difference is (a2 – a1) = 100