To Obtain thickness of cylinder
generally C = 2πr, therefore,
C1 = 2πr1
C2 = 2πr2
Lateral Surface Area, L, for a cylinder:
generally L = C * h = 2πrh, therefore,
L1 = 2πr1h, the external surface area
L2 = 2πr2h, the internal surface area
Area, A, for the end cross section of the tube:
generally A = πr2, for a circle, therefore,
A1 = πr12 for the area enclosed by C1
A2 = πr22 for the area enclosed by C2
A = A1 – A2 for the area of the solid cross section of the tube, the end.
A = π(r12 – r22)
Volume, V, for a cylinder:
generally V = A * h = πr2h, therefore,
V1 = πr12h for the volume enclosed by C1
V2 = πr22h for the volume enclosed by C2
V = V1 – V2 for the volume of the solid, the tube.
V = π(r12 – r22)h
Thickness of the tube wall, t:
t = r1 – r2
So, 2πrh = 338 π and h =10 cm
r = 338/20 = 16.9 cm.
so, please verify ur data again.