# To Obtain thickness of cylinder

Circumference, C:

generally C = 2πr, therefore,

C1 = 2πr1

C2 = 2πr2

Lateral Surface Area, L, for a cylinder:

generally L = C * h = 2πrh, therefore,

L1 = 2πr1h, the external surface area

L2 = 2πr2h, the internal surface area

Area, A, for the end cross section of the tube:

generally A = πr2, for a circle, therefore,

A1 = πr12 for the area enclosed by C1

A2 = πr22 for the area enclosed by C2

A = A1 – A2 for the area of the solid cross section of the tube, the end.

A = π(r12 – r22)

Volume, V, for a cylinder:

generally V = A * h = πr2h, therefore,

V1 = πr12h for the volume enclosed by C1

V2 = πr22h for the volume enclosed by C2

V = V1 – V2 for the volume of the solid, the tube.

V = π(r12 – r22)h

Thickness of the tube wall, t:

t = r1 – r2

So, 2πrh = 338 π and h =10 cm

r = 338/20 = 16.9 cm.

so, please verify ur data again.