sir, how to differentiation 4t – t square/2 + 2

Differentiation of 4t – (t^2)/2 + 2 is as follows:

d/dt [4t – (t^2)/2 + 2] = d/dt (4t) – d/dt[(t^2)/2] + d/dt(2) = 4(1.t^(1-1)) – 1/2[2.t^(2-1)] + 0 = 4(t^0) – 1/2[2.t^1] = 4 – t Ans.

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