This question is of cbse chapter2 polynomials

(4+v3)*(4-v3) =(4^2)-(v3^2) (due to (a+b)*(a-b) is equal to (a^2)-(b^2) so 4*4=16 v3*v3=3 then 16-3 =13.

This is the formula which you need to use…

(a+b)*(a-b) = a^2 – b^2 so, let 4 =a and v3 = b

so, it becomes 4^2 – v3^2 = 16 – 3 = 13.

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