If a diagonal of a parallelogram bisects one of the angles of the parallelogram,it also bisects the second angles. Also , prove it is a rhombus

Let ABCD is a parallelogram and AC bisects ∠A. Here, AB || CD and AC intersects them. Therefore, ∠1 = ∠4 (Alternate interior angles) Similarly, ∠2 = ∠3 (Alternate interior angles) But, ∠1 = ∠2 (AC bisects ∠A) Therefore, ∠3 = ∠4.

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