# numerical physices

Given, v₀ = 5 x 10⁶ m/s

v = 2.1 x 10⁶ m/s

s = 2.1 x 10⁻⁴ = 2.1 x 10⁻⁶ m

We know that,

v= v₀- at

a= (v₀-v)/t

and solve for ‘t’

a = (5 x 10⁶ – 2.1 x 10⁶)/t = 2.9 x 10⁶/t m/s^2

substitute ‘a’ in

s= v₀t+at²/2

s = 5 x 10⁶t + (2.9 x 10⁶/t) x t²/2

2 x 10⁻⁶ = 5 x 10⁶t + (2.9 x 10⁶/t) x t²/2

On solving,

t = 0.33 x 10^-12

t = 0.33 ps