# Newton’s laws of motion

Now, distance covered in these 4 sec: s1 = 91/2)(2)(4)^2 = 16 m (using the second equation of motion)

So, velocity after 4 sec = 2*4 = 8m/s (using the first equation of motion)

Thus, now the velocity will remain same = 8m/s

and the distance covered in remaining 6 sec = s2 = 6*8 = 48m

thus total distance = s1 + s2= 64m