x=7+√3 find √x + 1/√x

x = 7 + 4√3

Now, √x = √( 7 + 4√3 ) = √ [(√4)^2 + (√3)^2 + 2x√4x√3)] √x = (√4) + (√3) = 2 + √3

1 / √x = 1 / ( 2 + √3 ) Rationalizing the denominator, we get, 1 / √x = 2 – √3

So, √x + 1 / √x = 2 + √3 + 2 – √3 = 4

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