# find the volume of frustum.

The radius of the original cone is 8cm and the height is 12 cm.

Then, the volume of the original cone = 1\3(pi*r^2*h)=1\3*pi*(8)^2*(12)= 256pi

The cone is divided into two equal parts by drawing a plane through the mid points of its axis and parallel to the base.

Then, height of the top part will be half of the original height.

Then, the height of the small cone = {12}/{2}=6

And, the radius of the small cone = {8}/{2}=4

Volume of the small cone=1/3*pi*(4)^2*(6) =32pi

Therefore, volume of the frustum

=Volume of the original cone – Volume of the small cone

=256pi -32pi = 224pi

Compare the volume of the two part:

Volume of the frustum : Volume of the small cone = 224pi : 32pi

Volume of the frustum : Volume of the small cone=7:1

Answer : Required ratio of the two parts is 7:1