If the median of the series exceeds the mean by 3,find what number the mode exceeds its mean

3(median) = 2(mean) + mode Let the mean be ‘x’ So, median will be x + 3 Then, according to the question 3(x+3) = 2(x) + mode 3x + 9 = 2x + mode 3x – 2x + 9 = mode x+9 = mode Now, mode – mean ⇒ x+9 – x = 9

Hence, mode exceeds the mean by 9.

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