A particle is projected from the ground with a velocity of 25m/s .after 2seconds it just clears a wall 5m then the angle of projection [g=10m/s²]

Let angle of projection is Ɵ, then,

Ux = 25 cosƟ

Uy = 25 sinƟ

Given, after 2 sec it clears a wall of 5m height

H = Uyt – g(t^2)/2

5 = 25sinƟ*2 – 10*4/2

5 + 20 = 50sinƟ

sinƟ = 1/2

Ɵ = 30 degree

Hence, angle of projection is 30 deg

Call us: 90-26-27-28-29, 9157460799, 02614055508

Or, Fill out the form & get a call back.