abc ia an isosceles triangle with ab=ac.and d is a point on ac such that bc square=ac*cd.prove tht bd=dc
from the given info,
In triangles BCD and ACB,
Now, Angle BCD=angle ACB (Common Angle)
Hence, the two triangles are similar by SAS rule.
So, angle DBC= angle DCB (as they are corresponding angles of similar triangles)
i.e. angle DBC=angle ACB (as ACB and DCB are one and the same angle)
At last, for triangle DBC,
DB=BC (as sides opp equal angles are equal).